5x^2+16x=192

Solution for 5x^2+16x=192 equation:

5x^2+16x=192

We move all terms to the left:

5x^2+16x-(192)=0

a = 5; b = 16; c = -192;
Δ = b2-4ac
Δ = 162-4·5·(-192)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-64}{2*5}=\frac{-80}{10}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+64}{2*5}=\frac{48}{10}
=4+4/5
$